FAC1004 L18 — Hyperbolic Functions (Derivatives & Integrals)

Learning Outcome

To find and apply derivatives and integrals of hyperbolic functions.


Definitions (Recap)

The function $e^x$ can be expressed as the sum of an even function and an odd function:

$$e^x = \frac{e^x + e^{-x}}{2} + \frac{e^x - e^{-x}}{2}$$

  • Even function: hyperbolic cosine of $x$ $$\cosh x = \frac{e^x + e^{-x}}{2}$$

  • Odd function: hyperbolic sine of $x$ $$\sinh x = \frac{e^x - e^{-x}}{2}$$


Derivatives of Hyperbolic Functions

Derivatives for hyperbolic functions can be obtained by expressing the function in terms of $e^x$ and $e^{-x}$.

Derivation of $\frac{d}{dx}\sinh x$

$$\frac{d}{dx}[\sinh x] = \frac{d}{dx}\left[\frac{e^x - e^{-x}}{2}\right] = \frac{e^x + e^{-x}}{2} = \cosh x$$

Derivation of $\frac{d}{dx}\cosh x$

$$\frac{d}{dx}[\cosh x] = \frac{d}{dx}\left[\frac{e^x + e^{-x}}{2}\right] = \frac{e^x - e^{-x}}{2} = \sinh x$$

General Derivative Formulas (Chain Rule)

Let $u$ be a differentiable function of $x$:

Function Derivative
$\sinh u$ $\cosh u \cdot \frac{du}{dx}$
$\cosh u$ $\sinh u \cdot \frac{du}{dx}$
$\tanh u$ $\text{sech}^2 u \cdot \frac{du}{dx}$
$\coth u$ $-\text{csch}^2 u \cdot \frac{du}{dx}$
$\text{sech } u$ $-\text{sech } u \tanh u \cdot \frac{du}{dx}$
$\text{csch } u$ $-\text{csch } u \coth u \cdot \frac{du}{dx}$

Worked Examples

Example 1: Find $\frac{d}{dx}[\cosh(x^3)]$

$$\frac{d}{dx}[\cosh(x^3)] = \sinh(x^3) \cdot \frac{d}{dx}[x^3] = 3x^2 \sinh(x^3)$$

Example 2: Find $\frac{d}{dx}[\ln(\tanh x)]$

$$\frac{d}{dx}[\ln(\tanh x)] = \frac{1}{\tanh x} \cdot \frac{d}{dx}[\tanh x] = \frac{\text{sech}^2 x}{\tanh x}$$


Integrals of Hyperbolic Functions

The following theorem provides a complete list of the generalized integration formulas for hyperbolic functions.

Basic Integration Formulas

Integral Result
$\int \sinh u , du$ $\cosh u + C$
$\int \cosh u , du$ $\sinh u + C$
$\int \text{sech}^2 u , du$ $\tanh u + C$
$\int \text{csch}^2 u , du$ $-\coth u + C$
$\int \text{sech } u \tanh u , du$ $-\text{sech } u + C$
$\int \text{csch } u \coth u , du$ $-\text{csch } u + C$

Worked Examples

Example 1: Evaluate $\int \sinh^5 x \cosh x , dx$

Let $u = \sinh x$, then $du = \cosh x , dx$.

$$\int \sinh^5 x \cosh x , dx = \int u^5 , du = \frac{1}{6}u^6 + C = \frac{1}{6}\sinh^6 x + C$$

Example 2: Evaluate $\int \tanh x , dx$

Rewrite $\tanh x = \frac{\sinh x}{\cosh x}$.

Let $u = \cosh x$, then $du = \sinh x , dx$.

$$\int \tanh x , dx = \int \frac{\sinh x}{\cosh x} , dx = \int \frac{1}{u} , du = \ln u + C = \ln(\cosh x) + C$$


Summary

This lecture develops the calculus of hyperbolic functions. Key takeaways:

  1. Derivatives of hyperbolic functions follow patterns similar to trigonometric functions but with sign differences (no alternating sign for $\cosh x$).
  2. The chain rule applies to hyperbolic functions exactly as it does to trigonometric functions.
  3. Integration formulas are the reverse of differentiation formulas.
  4. Substitution techniques (u-substitution) are essential for evaluating hyperbolic integrals.

Related

Source File

LECTURE_NOTES_2526/L18 Hyperbolic Function full version.pdf